@lucidiot@tiny.tilde.website @BatElite this is just lambda calculus, which you don't need to know.

In haskell, the way to express the same thing is a little more simple:

(λf x → f x)

(or without special unicode: (\f x -> f x) )

@lizardsquid @lucidiot@tiny.tilde.website So how do you apply lizard to squid?

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