@lucidiot@tiny.tilde.website @BatElite this is just lambda calculus, which you don't need to know.
In haskell, the way to express the same thing is a little more simple:
(λf x → f x)
(or without special unicode: (\f x -> f x) )
@lizardsquid @lucidiot@tiny.tilde.website So how do you apply lizard to squid?
@BatElite @lucidiot@tiny.tilde.website oh my gosh I'm giggling